How to aggregate switches?

Good day :)

On Board are 6 of the switch 2960.

Use the EtherChannel technology.

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Don't quite understand how to work this scheme if all chanell-group 1 mode on.
I understand that I get 400 velocity :) But can not see the difference :)
And whether I did it?

Or have the group spread out like this:

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June 26th 19 at 14:07
2 answers
June 26th 19 at 14:09
Solution
Take a look:
1. How to set up balancing?
2. How measured speed?

These questions are related, actually: in order to understand which port LAG to shove an Ethernet frame, the switch computes a hash function is chosen in the setup field of the frame and takes the remainder of dividing the hash by the number of links in the LAG.

Default generally is considered to be a hash of the Source MAC + Destination MAC.
Also, usually you can enable the use for hash computation:
- Source ip/Destination ip
- Source port/Destination port

In practice, this means that:
1. The more raznyh MAC/ip addresses passes through the LAG, there is more evenly distributed traffic
2. But the established TCP connection is not "smeared" at the links and, for example, download a file via FTP the speed will still run at the speed of a single link, whether they are there at least eight
June 26th 19 at 14:11
Solution
I understand that I get 400 on speeds :)

No, the etherchannel is primarily a technology of fault tolerance, not throughput links

Don't quite understand how to work this scheme if all chanell-group 1 mode on

group numbers have local significance and do not necessarily coincide on different switches
No, the etherchannel is primarily a technology of fault tolerance, not throughput links


No, the throughput also increases.
But there is a caveat - the hash function on which Ethernet frames are scattered across the physical links. - Troy.Hermiston commented on June 26th 19 at 14:14
I understand increases, but it is not equal to the amount included in the etherchannel links. I'm talking about - francesca commented on June 26th 19 at 14:17

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