In jQuery, when a sample of class where the name should point out what to do?

For example:
$(".nameClass.") - gives an error. How to be?
June 3rd 19 at 21:02
2 answers
June 3rd 19 at 21:04
Solution
$('.nameClass\\.')
June 3rd 19 at 21:06
Solution
$('[class*="nameClass."]')

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