Error in the class when you create a variable?

Question

Error in the class when you create a variable?

Actually:

It is clear that if you make public $now = '2016-05-28'; then it works but how so?

PHP

Clovis_Gulgowski43 asked July 9th 19 at 10:31

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More answers about "Error in the class when you create a variable?"

1 answer

Marcus.Wolff answered on · Accepted Answer · 2019-07-09T10:33:33.845Z

Marcus.Wolff answered on July 9th 19 at 10:33

Solution

Because it is impossible to define properties to use expressions.
Do initialization of properties in the class constructor.

Could you elaborate about this design:

class SimpleClass{
 public $now = ";

 function __construct() {
 $now = date("Y-m-d"); 
}

 public function display_now() {
 echo $this->now;
var_dump($this->now);
}
}

$b = new SimpleClass();
$b->display_now();

- Why can't he override it in the constructor and outputs string(0) "" - Clovis_Gulgowski43 commented on July 9th 19 at 10:36

: because in the constructor you need to write not $now, $this->now - Marcus.Wolff commented on July 9th 19 at 10:39

: and Yes, I'm lame, get used to OOP in any way, thank you )) - Clovis_Gulgowski43 commented on July 9th 19 at 10:42