Gulp how to make 2 files, linking libraries in a separate file and the file common.js?

Question

Gulp how to make 2 files, linking libraries in a separate file and the file common.js?

If you just combine all the js files and connect custom scripts do not work. Need to connect jikiri. But jikiri is United file libraries and there custom scripts, but it doesn't work. It should be the same that would javeri was connected first.
Now I have in the js folder, all the plugins, libraries and custom skrypty.
My task

gulp.task('js', function() {
 return gulp.src('frontend/assets/js/*.js')
.pipe(concat('all.min.js'))
.pipe(uglify())
.pipe(gulp.dest('public/js'));
});

Gulp.js

toby asked July 9th 19 at 10:47

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More answers about "Gulp how to make 2 files, linking libraries in a separate file and the file common.js?"

1 answer

Missouri.Terry answered on · Accepted Answer · 2019-07-09T10:49:28.719Z

Maybe not quite understand your question, as it is slyly wise you asked it, but for example all the builds sent in the form of 2 files: main.js and vendor.js in principle, the same train, and with styles. What about Tusk, here's an example of my some libraries (not essential):

// ~ Compile JS ~
var jsFilter = gulpFilter('**/*.js');

// Concat vendor JS (uglify for production)
gulp.task('js:vendor', function() {
gulp.src(mainBowerFiles({
 "overrides": {
 "jquery": {
 "main": "./dist/jquery.min.js"
},

 "bootstrap": {
 "main": "./dist/js/bootstrap.min.js"
},

 "magnific-popup": {
 "main": "./dist/jquery.magnific-popup.min.js"
}
}
}))
.pipe(jsFilter)
.pipe(concat('vendor.js'))
 .pipe(gulpIf(env !== 'dev', uglify()))
 .pipe(gulp.dest(outputDir + 'js'))
});

// Concat own JS (uglify for production)
gulp.task('js', function() {
gulp.src(src.js)
.pipe(jsHint())
.pipe(jsHint.reporter('default'))
.pipe(concat('script.js'))
 .pipe(gulpIf(env !== 'dev', uglify()))
 .pipe(gulp.dest(outputDir + 'js'))
.pipe(connect.reload());
});

configuration is performed depending on production or development version