Problem with YQL?

Hello. Trying to do a query against this XML file: c using YQL. The query seems to be generated correctly:
select * from data where url="" and xpath="*"
Link to the console

But, the response States that this "table" is not.

If you store data instead of html
select * from html where url="" and xpath="*"

Then comes a blank html file with a meta janowskie

 <meta content="HTML Tidy for Java (vers. 26 Sep 2004), see" name="generator">
 <meta id="C0018787">
the <body/>
I suspect that encodeURICommponent (or similar function) distorts the query so that it is sent to a completely different address, not to <a href="" rel="nofollow" target="_blank"></a><br><br><br>
How to be?</title>
October 8th 19 at 01:21
1 answer
October 8th 19 at 01:23
Describe rules for parsing of 'data'.
And since everything is normal is: link
How to describe — - Florine_Yundt commented on October 8th 19 at 01:26
Hmm, not really understand. The article described what you have brought on the first link. - Lewis51 commented on October 8th 19 at 01:29
I just showed an example how correctly to receive information from the external resource. But how to define data to be written to you. - Florine_Yundt commented on October 8th 19 at 01:32
Unfortunately, I have not found definitions. - Lewis51 commented on October 8th 19 at 01:35

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