The mass lost by Sun per second

I understand that the question is not relevant, but I think that on habré a lot of people with good knowledge of physics. Today helped the younger brother to solve problems in physics, one is soporose and wild interest was inflating me. Myself quantum physics and optics like a good idea remember, though it's been 4 years, but then a complete stupor, it is interesting to understand.

In tasks with only a full flow of energy radiated by the sun. From what ottolknutsya, tell me?
October 8th 19 at 02:37
6 answers
October 8th 19 at 02:39
October 8th 19 at 02:41
Take the mass of the sun in any arbitrary moment in time and subtract its weight in one second, the difference will be the answer.
October 8th 19 at 02:43
Roughly (for a blackbody):

Temperature 6000 K, time 1 sec, the radius of 700,000 km, the speed of light and the Stefan-Boltzmann constant known
Damn. Inadvertently could that the left side is known and so :) - mittie commented on October 8th 19 at 02:46
The middle equation is generally valid because, AFAIK, it only works for thermal electromagnetic radiation. And there is also nonthermal gamma-ray and charged particles. - nikita.Stracke commented on October 8th 19 at 02:49
October 8th 19 at 02:45
The first link in Google:
3. Weight, lose the Sun for 1, we define by applying the law of equivalence of mass and energy
And what does quantum physics? Already the school run? - mittie commented on October 8th 19 at 02:48
This section of the Optics. Brother to 1m course. - nikita.Stracke commented on October 8th 19 at 02:51
Thanks for the link, the morning googling found nothing similar... - rhianna_Rutherford commented on October 8th 19 at 02:54
October 8th 19 at 02:47
Easy. Need to know the number of energy that the Sun plays in the process of radiation and decay.
Ie how many emit energy in the hour/second? This is possible through E= mc^2 to calculate the weight loss :)
October 8th 19 at 02:49

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