Why, after the diode bridge is a capacitor on 63В?

Why, after the diode bridge is a capacitor on 63В? Due to what it decreases?
If you can tell me how to do the calculation.
vkluchenie-sveta3.jpg
June 8th 19 at 16:39
2 answers
June 8th 19 at 16:41
see parameters VS2 and it's all about + working principle (Google as "the dynistor db3").
the purpose of the scheme to the right of the bridge is unclear, and generally the scheme as a whole.
if simple then "load" of the bridge feeds on a segment of a sine wave "- ......30V 0V+30V" through the lamp EL1. the lamp itself is not included and Vice versa.
this should be the schema of a smooth inclusion of lamps - alex.Sipes commented on June 8th 19 at 16:44
nope, the voltage limits are not the dynistor and resistor R1.
Right, this is the device for smooth switching of the lamp.
I don't know what formulas to check resistor values. I want to put another transistor, I don't want anything exploded. - Joany.Considi commented on June 8th 19 at 16:47
June 8th 19 at 16:43
the voltage limits are not the dynistor and resistor R1.
It is a question of terminology. In fact, don't be dynistor, the voltage on C1 would rise further, but the dynistor does not allow this to happen when you exceed 30 volts - discharge C1 at a control input of the thyristor. So the limitation circuit is not R1, and R1+VS2.
By the way, this means that the initial portion of the sine wave (0 to 30 volts) is not used for glow lamps, the brightness is less than nominal.
Why, after the diode bridge is a capacitor on 63В?
For the same reason - the voltage there (with the correct operation of the circuit, of course) not supposed to reach 63 volts.

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