What is the error in the script?

Question

What is the error in the script?

Everything is OK:

$a = 'output';
eval("echo \"$a\";");

So

$a = 'output';
eval("echo $a;");

Notice: Use of undefined constant output - assumed 'conclusion' in ...test.php(5) : eval()'d code on line 1
conclusion

Where he sees a constant? OK, will do:

$a = '\'withdrawal\";
eval("echo \"$a\";");

On the screen 'conclusion' (with quotation marks).
So PHP it has to be like in echo 'output'; and then on the screen the word without quotation marks should be shown?

PHP

shaniya asked June 8th 19 at 17:29

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More answers about "What is the error in the script?"

1 answer

sofia.Maggio answered on · Accepted Answer · 2019-06-08T17:31:33.876Z

sofia.Maggio answered on June 8th 19 at 17:31

Solution

$a = 'output';
eval("echo $a;");

All logically correct, PHP searches for variables in double quotes and of course framing values.
So:

eval("echo output");

It's like this:

$a = 'output';
eval('echo $a;');