How in Python to sort the list in ascending order?

Get a list of files in the folder:
files = os.listdir('html')
for x in files:
 print(x)

The conclusion is:
80
43
53
120
157
66
136
168
87
92

When to use the list method sort () it sorts wrong with me:
After sort()

0
1
10
100
101
102
103
104
105
106
107
108
109
11
110
111
112
113
114
115
116
117
118
119
12
120
121
122
123
124
125
126
127
128
129
13
130
131
132
133
134
135
136
137
138
139
14
140
141
142
143
144
145
146
147
148
149
15
150
151
152
153
154
155
156
157
158
159
16
160
161
162
163
164
165
166
167
168
169
17
170
171
172
173
174
175
176
177
178
179
18
180
181
182
183
184
185
186
187
188
189
19
190
191
192
193
194
195
196
197
198
199
2
20
21
22
23
24
25
26
27
28
29
3
30
31
32
33
34
35
36
37
38
39
4
40
41
42
43
44
45
46
47
48
49
5
50
51
52
53
54
55
56
57
58
59
6
60
61
62
63
64
65
66
67
68
69
7
70
71
72
73
74
75
76
77
78
79
8
80
81
82
83
84
85
86
87
88
89
9
90
91
92
93
94
95
96
97
98
99

But I need to go in order. Google something not helped. I am sure that the solution is simple. Thank you!
April 4th 20 at 12:56
2 answers
April 4th 20 at 12:58
Solution
list.sort(key=int)
Then the pre-sort function converts the elements to int
Thank you! Completely forgot that I have a list of strings, not numbers. Did a bit differently:
result = [int(item) for item in files] - jordi_Olson commented on April 4th 20 at 13:01
April 4th 20 at 13:00
Specifically for your case, @Kaci.Jerde83 brought an acceptable solution.
I'm with a similar problem was encountered when doing the CLI utility of forming playlists for audiobooks.
There had to correctly sort the file with the chapters of the book, the numbered files contain the text placed in subdirectories (also numbered and with text).

The name of each file Parcelas (divided) into its constituent parts, was formed and the sorting key here is such a function:
def filename_key(fn: Path, root: Path = None) -> typing.Hashable:
 def split(s: str, re_splitter=re.compile(r'(\D+|\d+)')) -> tuple:
 return tuple(int(chunk) if chunk.isdigit() else chunk for chunk in re_splitter.split(s) if chunk)

 rel_path = fn.relative_to(root) if root else fn
 return tuple(split(name) for name in rel_path.parent.parts) + (split(rel_path.stem) + (rel_path.suffix,),)

You can apply this:
my_files = (f for f in my_folder_path.rglob('*.mp3'))
my_sorted_files = sorted((
 (filename_key(f, root=my_folder_path), f) 
 for f in my_files
))
Thanks for the reply. Specifically, in my case, it was my carelessness. On my list were a string, and I was trying to sort a list of numbers. - jordi_Olson commented on April 4th 20 at 13:03

Find more questions by tags Python