As algebraicheskie round in Python3.6?
Hi, I need to round a number Python3 algebraic rounding (not banking that in Python3 by default).
Simply put, I need:
round(0.5) 1 round(0.6) 1 round(0.4) 0
June 10th 19 at 14:40
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"As algebraicheskie round in Python3.6?"
June 10th 19 at 14:42
Use the search function.
In python rounding 2.5 to 3?
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