As algebraicheskie round in Python3.6?

Hi, I need to round a number Python3 algebraic rounding (not banking that in Python3 by default).

Simply put, I need:

round(0.5)
1
round(0.6)
1
round(0.4)
0
June 10th 19 at 14:40
1 answer
June 10th 19 at 14:42
Solution
Use the search function.
In python rounding 2.5 to 3?

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